2nd Comm., The Problemist Supplement, 2007
#3
The solution to last week’s puzzle, posted as a tribute to the late Colin Russ, is:
- Ra7!
If 1… g5, then 2. Kg4 followed by 3. B(x)f5#.
If 1… f5, then 2. Ba6 followed by 3. Bc8#.
If 1… f6, then 2. Bxg6 folllowed by 3. Bf7#